(2x^2D^2+4xD+7)y=logx^2

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Solution for (2x^2D^2+4xD+7)y=logx^2 equation: 


Simplifying
(2x2D2 + 4xD + 7) * y = logx2

Reorder the terms:
(7 + 4xD + 2x2D2) * y = logx2

Reorder the terms for easier multiplication:
y(7 + 4xD + 2x2D2) = logx2
(7 * y + 4xD * y + 2x2D2 * y) = logx2

Reorder the terms:
(4xyD + 2x2yD2 + 7y) = logx2
(4xyD + 2x2yD2 + 7y) = logx2

Solving
4xyD + 2x2yD2 + 7y = glox2

Solving for variable 'x'.

Reorder the terms:
-1glox2 + 4xyD + 2x2yD2 + 7y = glox2 + -1glox2

Combine like terms: glox2 + -1glox2 = 0
-1glox2 + 4xyD + 2x2yD2 + 7y = 0

The solution to this equation could not be determined.

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